wiz-icon
MyQuestionIcon
MyQuestionIcon
5
You visited us 5 times! Enjoying our articles? Unlock Full Access!
Question

A, B, C, D are 4 non collinear points in a plane such that ACB = ADB, then how many circle(s) can be drawn passing through all 4 points.


A

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

False


Let us draw the points A, B, C, D such that ACB =ADB.

Now, draw a circle through A, B, C. Let us assume that the circle does not pass through the point D but intersects the extension of line segment CD at D.

Since, angles subtended by an arc in a segment are equal, ACB =ADB. It is given that ACB =ADB. Thus, for the angles to be equal, D and D should coincide. Thus, our assumption that the circle does not pass through D is wrong.

Therefore, only one circle can be drawn through these 4 points.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorem of Cyclic Quadrilateral
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon