A, B, C, D are 4 non-collinear points in a plane such that ∠ ACB=∠ ADB, then how many circle(s) can be drawn passing through all 4 points.
False
Let us draw the points A, B, C, D such that ∠ACB = ∠ADB.
Now draw a circle through A, B, C. Let us assume that the circle does not pass through the point D but intersects the extension of line segment CD at D′.
Since angles subtended by an arc in a segment are equal, ∠ ACB=∠A D′B. It is given that ∠ACB=∠ADB. Thus for the angles to be equal, D and D′ should coincide. Thus our assumption that the circle does not pass through D is false.
Therefore a circle can be drawn through these 4 points.