Question

A, B, C, D are mid points of sides of parallelogram PQRS. IF $ar\left(PQRS\right)=36c{m}^2$, then ar (ABCD) =

• A. $24c{m}^2$
• B. $18c{m}^2$
  
• C. $30c{m}^2$
  
• D. $36c{m}^2$
  

Answer 1

The correct option is B

$18c{m}^2$

A, B, C and D are the midpoints of sides of a ||gm PQRS.
Area of PQRS $=36c{m}^2$

The area of ||gm formed by joining AB, BC, CD and DA
$\frac{1}{2}ar\left(||gmPQRS\right)$

$=\frac{1}{2}\times 36=18c{m}^2$