$a, b, c, d, e$ are in $A . P$ . Prove the following results
$a - 2 b + c = 0$

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Solution

We have,
$a, b, c, d, e$ are in $A . P .$

So, $b - a = c - b = d - c = e - d$

Therefore,
$b - a = c - b$
$a - 2 b + c = 0$

Hence, proved.

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