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Question

ABCD is a quadrilateral, E is the point of intersection of the line joining the middle points of the opposite sides. lf O is any point, then ^OA+^OB+^OC+^OD=

A
4^OE
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B
3^OE
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C
2^OE
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D
^OE
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Solution

The correct option is A 4^OE
Let PV (position vector) of A,B,C,D be a,b,c,d respectively.
PV of P = a+b2
PV of Q = c+d2
PV of v = a+d2
PV of u = b+b2
PQ=12(da+cb)
uv=12(ab+dc)
So, E=a+b++c+d4
Let O be origin, so OA+OB+OC+OD=a+b+c+d
Therefore, 4OE=a+b+c+d
58017_34188_ans_23af3b9047644cab8d03cc6c8cc7a82c.png

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