ABCD is a quadrilateral, E is the point of intersection of the line joining the middle points of the opposite sides. lf O is any point, then ^OA+^OB+^OC+^OD=
A
4^OE
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B
3^OE
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C
2^OE
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D
^OE
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Solution
The correct option is A4^OE Let PV (position vector) of A,B,C,D be →a,→b,→c,→d respectively. PV of P=→a+→b2 PV of Q=→c+→d2 PV of v=→a+→d2 PV of u=→b+→b2 →PQ=12(→d−→a+→c−→b) →uv=12(→a−→b+→d−→c) So, E=→a+→b+→+c+→d4 Let O be origin, so →OA+→OB+→OC+→OD=→a+→b+→c+→d Therefore, 4→OE=→a+→b+→c+→d