Question

$A,B,C$ try to hit a target simultaneously but inside- target are $\frac{3}{4},\frac{1}{2},\frac{5}{8}$, the probability that target is bur by $A$ or $B$ but not by $C$ is

• A. $\frac{21}{64}$
• B. $\frac{7}{8}$
• C. $\frac{7}{32}$
• D. $\frac{9}{64}$

Answer 1

The correct option is A $\frac{21}{64}$

Probability will be $=\left(\frac{3}{4}\right)\left(\frac{1}{2}\right)\left(\frac{3}{8}\right)+\left(\frac{1}{4}\right)\left(\frac{1}{2}\right)\left(\frac{3}{8}\right)+\left(\frac{3}{4}\right)\left(\frac{1}{2}\right)\left(\frac{3}{8}\right)$

$=\frac{12+9}{64}=\frac{21}{64}=\frac{21}{64}$