The correct options are
A 1 mol of A3B2C2 is formed.
C 43 mol of A3B2 is formed.
D 13 mol of A3B2 is left at the end.
The balanced reactions are as follows:
3A+2B→A3B2
4 4 43 formed.............................(in moles)
A3B2+2C→A3B2C2
43 2 0................................(in moles) (Initial)
13 0 1................................(in mole) (Final)
Hence, options A, C and D are correct.