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Question

A+BA3B2
A3B2+CA3B2C2

The above two reactions are carried out by taking 4 moles each of A and B and 2 moles of C. Which of the following option(s) is/are correct?

A
1 mol of A3B2C2 is formed.
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B
12 mol of A3B2C2 is formed.
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C
43 mol of A3B2 is formed.
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D
13 mol of A3B2 is left at the end.
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Solution

The correct options are
A 1 mol of A3B2C2 is formed.
C 43 mol of A3B2 is formed.
D 13 mol of A3B2 is left at the end.
The balanced reactions are as follows:
3A+2BA3B2
4 4 43 formed.............................(in moles)
A3B2+2CA3B2C2
43 2 0................................(in moles) (Initial)
13 0 1................................(in mole) (Final)
Hence, options A, C and D are correct.

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