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B
a3−b3+2a2b−2ab2+ab2−ba2
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C
2a2b+2ab2
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D
a3+b3+2a2b+2ab2+ab2+ba2
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Solution
The correct option is Ba3−b3+2a2b−2ab2+ab2−ba2 (a−b)×(a2+2ab+b2) =(a×a2+a×2ab+a×b2)+((−b)×a2+(−b)×2ab+(−b)×b2=a3+2a2b+ab2−ba2−2ab2−b3=a3−b3+2a2b−2ab2+ab2−ba2