Question

$AB$
$\underset{–}{\times 5}$
$\underset{–}{CAB}$

Find $A+B+C$.

• A. $7$
• B. $9$
• C. $15$
• D. $10$

Answer 1

The correct option is A $7$

$AB\times 5=CAB,$

$(10A+B)\times 5=100C+10A+B,$

$50A+5B=100C+10A+B$

$40A+4B=100C$

$B=5,$ then $38A=100C$ not possible.

$B=0,$ then $40A=100C$

Only possible values are $A=5,C=2$

Therefore $A+B+C=7$

Thus, the answer is $7$.