A bacterial dsDNA molecule, 2988bp in length, was found to have the following composition:
T
C
A
G
Strand I
348
X
348
1400
Strand II
650
650
Y
The respective values of X and Y are :
A
1400 and 590
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B
590 and 1400
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C
590 and 590
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D
None of the above
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Solution
The correct option is C590 and 590 As this DNA strand contains 2988 base pairs. So, the total number of nucleotides from strand 1 must be equal to 2988.
So, 348+X+640+1400 = 2988
After solving we get X = 590
Also, the number of cytosine from one strand is equal to guanine from another strand, hence Y = 590.