Question

A badminton player won 6 games and lost 4.The fraction of the games he won is

• A. $\frac{6}{4}$
• B. $\frac{4}{6}$
• C. $\frac{6}{10}$
• D. $\frac{5}{10}$

Answer 1

Answer: (C)

$\frac{6}{10}$

Games won = 6
Total Games = $6+4=10$
$\therefore$ required fraction = $\frac{6}{10}$