Question

A badminton player won $6$ games and lost $4$. The fraction of the games he won is

• A. $\frac{6}{4}$
• B. $\frac{4}{6}$
• C. $\frac{6}{10}$
• D. $\frac{5}{10}$

Answer 1

The correct option is C $\frac{6}{10}$

Games won $=6$
Total games $=6+4=10$
$\therefore$ required fraction = $\frac{6}{10}$