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Standard XII

Mathematics

Combination

A bag contain...

Question

A bag contain $50$ cads numbered $1, 2, 3, . . . . . 49, 50$ . A cards is chosen, what is probability that the card contain a 2 digit number?

\frac{4}{5}

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\frac{41}{50}

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\frac{41}{49}

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\frac{1}{2}

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Solution

The correct option is B $\frac{41}{50}$
Total number of cards: $50$
Total number of two digit numbers: $41$
Required probability: $P = \frac{41}{50}$

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Similar questions

Q. A bag contains 16 cards bearing numbers 1, 2, 3, ..., 16 respectively. One card is chosen at random. What is the probability that the chosen card bears a number divisible by 3?
(a)

\frac{3}{16}

(b)

\frac{5}{16}

(c)

\frac{11}{16}

(d)

\frac{13}{16}

A bag contains 16 cards bearing number 1, 2, 3, . . . , 16 respectively. One card is chosen at random. What is the probability that the chosen card bears a number which is divisible by 3?

(a) $\frac{3}{16}$

(b) $\frac{5}{16}$

(d) $\frac{13}{16}$

A bag contains cards numbers from 1 to 49. A card is drawn from the bag at random, after mixing the cards thoroughly. Find the probability that the number on the drawn card is:
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A bag contains cards which are numbered from 2 to 90. A card is drawn at random from the bag. The probability that it bears a two digit number is:

Q. Box

1

contains three cards bearing numbers

1, 2, 3;

box

2

contains five cards bearing numbers

1, 2, 3, 4, 5;

and box

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contains seven cards bearing numbers

1, 2, 3, 4, 5, 6, 7.

A card is drawn from each of the boxes. Let

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i^{t h}

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A bag contain 50 cads numbered 1,2,3,.....49,50. A cards is chosen, what is probability that the card contain a 2 digit number?

The correct option is B 4150Total number of cards: 50Total number of two digit numbers: 41Required probability: P=4150

A bag contain $50$ cads numbered $1, 2, 3, . . . . . 49, 50$ . A cards is chosen, what is probability that the card contain a 2 digit number?

The correct option is B $\frac{41}{50}$
Total number of cards: $50$
Total number of two digit numbers: $41$
Required probability: $P = \frac{41}{50}$