Question

A bag contains 10 red balls and 7 blue balls. A ball is drawn at random. The probability that ball drawn is not red is

• A. $\frac{7}{10}$
• B. $\frac{3}{17}$
• C. $\frac{10}{17}$
• D. $\frac{7}{17}$

Answer 1

Answer: (D)

$\frac{7}{17}$

Total Red balls: $10$

Total blue balls: $7$

Total Balls: $10+7=17$

Probability of ball drawn is a red ball:

$P\left(Red\right)=\frac{10}{17}$

Probability of ball drawn is not a red ball:

$P\left(notred\right)=1-P\left(Red\right)=1-\frac{10}{17}=\frac{7}{17}$