Question

A bag contains 12 red, 15 white and 8 black balls. If a ball is drawn at random from the bag, then what is the probability that the ball drawn is

(a) Red

(b) White

(c) Black

• A.
  $\frac{12}{36},\frac{11}{36},\frac{13}{36}$
  
• B.
  
  $\frac{12}{35},\frac{3}{7},\frac{8}{35}$
  
• C.
  $\frac{12}{35},\frac{5}{35},\frac{11}{7}$
  
• D.
  $\frac{13}{36},\frac{12}{36},\frac{11}{36}$
  

Answer 1

The correct option is B


$\frac{12}{35},\frac{3}{7},\frac{8}{35}$

$P\left(ϵ\right)=\frac{\text{No of favourable outcome}}{\text{Total no of outcomes}}$

Total no of balls = 12+15+8 = 35

Probability that a red ball is drawn $=\frac{12}{35}$

Probability that a white ball is drawn $=\frac{15}{35}=\frac{3}{7}$

Probability that a black ball is drawn $=\frac{8}{35}$ So, the correct option is option (b).