A bag contains 12 white and black balls out of which $x$ are black. If one ball is drawn at random, what is the probability it will be a white ball ?

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Solution

The correct option is B
Total number of balls = 12

Total number of black balls $= x$

P (getting a black ball) $= \frac{x}{12}$

So, probability of getting a white ball $= \frac{(12 - x)}{12}$

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A bag contains 12 white and black balls out of which x are black. If one ball is drawn at random, what is the probability it will be a white ball ?

The correct option is B Total number of balls = 12 Total number of black balls =x P (getting a black ball) =x12 So, probability of getting a white ball =(12−x)12

A bag contains 12 white and black balls out of which $x$ are black. If one ball is drawn at random, what is the probability it will be a white ball ?

The correct option is B
Total number of balls = 12

Total number of black balls $= x$

P (getting a black ball) $= \frac{x}{12}$

So, probability of getting a white ball $= \frac{(12 - x)}{12}$