Question

A bag contains $13$ balls numbered from $1$ to $13$. Suppose drawing of an even number is a sucess. Two balls are drawn with replacement from the bag. The probability of getting two successes is

• A. $\frac{84}{169}$
• B. $\frac{49}{169}$
• C. $\frac{36}{169}$
• D. $\frac{120}{169}$

Answer 1

The correct option is C $\frac{36}{169}$

Given that drawing an even number is success out of total $13$ possible outcomes so

$P\left(S\right)=\frac{6}{13}$

Probability of failure $=P\left(F\right)=\frac{7}{13}$

Probability of getting two success out of two drawn $=(\frac{6}{13}{)}^2=\frac{36}{169}.$