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A bag contains $$15$$ red, $$8$$ blue and several green marbles. A marble is selected at random. The probability of drawing a blue marble is $$\dfrac {1}{5}$$. 
$$5$$ green marbles are now taken out from the bag. If a marble is now drawn at random, find the probability of drawing a green marble


A
310
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B
1235
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C
2340
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D
1735
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Solution

The correct option is B $$\dfrac {12}{35}$$
A bag contains 15 red, 8 blue and several green marbles. A marble is selected at random. The probability of drawing a blue marble is $$\dfrac{1}{5}$$. 
5 green marbles are now taken out from the bag. If a marble is now drawn at random,
The green marble are $$\dfrac{8}{P(E)}-(15+8)=40-23=17$$
if 5 marbles are removed green marbles are $$=17-5=12$$ and total marbles 40-5=35 
the probability of drawing a green marble
Probability  is $$P(E)=\dfrac{12}{35}$$

Mathematics

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