Question

A bag contains 155 Rupees in the form of 1 rupee,50 Paisa,a and 10 Paisa coins in the ratio of 3:5:7 . Find the number of each type of coins

Answer 1

Let ratio coefficient = x

And ratio of 1 rupee , 50 paise and 10 paise coins 3 : 5 : 7

So,

1 rupee coins = 3 x

50 paise coins = 5 x

And

10 paise coins = 7 x

And total money = 155 , So

1 ( 3 x ) + 0.5 ( 5 x ) + 0.1 ( 7 x ) = 155

3 x + 2.5 x + 0.7 x = 155

6 . 2 x = 155

x = 25

So,

1 rupee coins = 3 ( 25 ) = 75

50 paise coins = 5 ( 25 ) = 125

And

10 paise coins = 7 ( 25 ) = 175