Question

A bag contains 17 tickets numbered from 1 to 17. A ticket is drawn at random, then another ticket is drawn without replacing the first one. The probability that both the tickets may show even numbers is

• A. $\frac{7}{34}$
• B. $\frac{8}{17}$
• C. $\frac{7}{16}$
• D. $\frac{7}{17}$

Answer 1

The correct option is A $\frac{7}{34}$

There are 8 even numbers between 1 and 17.
Let $A$ be the probability that first ticket shows even number and $B$ be the probability that second ticket shows even number.
We have to find $P(A\cap B)$
$P(A\cap B)=P\left(A\right).P\left(B|A\right)$
$=\frac{8}{17}\times \frac{7}{16}=\frac{7}{34}$