Question

A bag contains $187$ in the form of $1$ rupee,$50$ paise and $10$ paise coin in the ratio $3:4:5$.Find the number of each type of coins?

Answer 1

Let the number of $1$ rupee,$50$ paise and $10$ paise coins be $3x,4x$ nd $5x$ respectively.

Then,$3x+4x\times \frac{50}{100}+5x\times \frac{10}{100}=187$

$\Rightarrow 3x+2x+\frac{x}{2}=187$

$\Rightarrow 5x+\frac{x}{2}=187$

$\Rightarrow \frac{10x+x}{2}=187$

$\Rightarrow \frac{11x}{2}=187$

$\Rightarrow x=17\times 2=34$

$\therefore 3x=3\times 34=102$

$4x=4\times 34=136$ and $5x=5\times 34=170$

Thus, the number of $1$ rupee ,$50$ paise and $10$ paise coins are $102,136$ and $170$ respectively.