A bag contains 19 red balls, 37 blue balls and 27 green balls. If a ball is picked up from this bag at random, What is the probability of picking a blue ball?

\frac{19}{8}

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\frac{9}{83}

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\frac{19}{83}

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None of the above

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Solution

The correct option is B None of the above
Number of blue ball = 37
Total number of ball = 19 + 37 + 27 = 83
Probability of picking blue ball = $\frac{37}{83}$

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A bag contains 19 red balls, 37 blue balls and 27 green balls. If a ball is picked up from this bag at random, What is the probability of picking a blue ball?

The correct option is B None of the aboveNumber of blue ball = 37Total number of ball = 19 + 37 + 27 = 83Probability of picking blue ball = 3783

The correct option is B None of the above
Number of blue ball = 37
Total number of ball = 19 + 37 + 27 = 83
Probability of picking blue ball = $\frac{37}{83}$