Question

A bag contains $25$ pieces of candies. There are $10$ grapes, $7$ cherries, $3$ lemons, $5$ strawberries. What are the odds against drawing a lemon?

• A. $\frac{22}{3}$
• B. $\frac{25}{3}$
• C. $\frac{3}{22}$
• D. $\frac{3}{25}$

Answer 1

The correct option is A $\frac{22}{3}$

$\underset{–}{\text{Given}:}$
In a bag of $25$ pieces of candies
$\bullet$ Number of grapes $=10$
$\bullet$ Number of cherries $=7$
$\bullet$ Number of lemons $=3$
$\bullet$ Number of strawberries $=5$

$\underset{–}{\text{Need to Find}:}$
Odds against drawing a lemon

Here,
Number of favorable outcomes
$=$ Number of lemons
$=3$

Number of unfavorable outcomes
$=$ Total number of candies $-$
Number of lemons
$=25-3=22$

$\text{Odds against drawing a lemon}=\frac{\text{Number of unfavorable outcomes}}{\text{Number of favorable outcomes}}$

$\Rightarrow \text{Odds against drawing a lemon}=\frac{22}{3}$

Therefore, option (a.) is the correct choice.