Question

A bag contains 3 red, 3 white and 3 green balls. One ball is taken out of the bag at random. What is the probability that the ball drawn is:
(1) red.
(2) not red
(3) either red or white.
$\left[3\right]$

Answer 1

Solution:
Number of Red balls = 3
Number of White balls = 3
Number of Green balls = 3

Total number of balls = 9

(1) Probability of drawing a red ball = $\frac{NumberofRedballs}{Totalnumberofballs}=\frac{3}{9}=\frac{1}{3}$
[1 Mark]

(2) Probability of drawing not a red ball =$\frac{NumberofWhiteandGreenballs}{Totalnumberofballs}=\frac{6}{9}=\frac{2}{3}$
[1 Mark]

(3) Probability of drawing either red or white ball =$\frac{NumberofRedorWhiteballs}{TotalNumberofballs}=\frac{6}{9}=\frac{2}{3}$
[1 Mark]