Question

A bag contains $3$ white, $2$ black and $4$ red balls.The probability of drawing a white, a black and a red ball in succession in that order without replacement is

• A. $\frac{8}{243}$
• B. $\frac{1}{21}$
• C. $\frac{5}{21}$
• D. $\frac{3}{21}$

Answer 1

The correct option is B $\frac{1}{21}$

A bag contains: $3W+2B+4R=9$
Probability of getting $1W+1B+1R$ ball from this bag without replacement:
$=\left(\frac{3}{9}\right)\times \left(\frac{2}{8}\right)\times \left(\frac{4}{7}\right)=\frac{1}{21}$