Question

A bag contains $3$ white, $2$ black and $4$ red balls.Three balls are drawn one after another with replacement at random. The probability of drawing a white, a black, and a red ball in succession in that order is

• A. $\frac{1}{21}$
• B. $\frac{5}{21}$
• C. $\frac{8}{243}$
• D. $\frac{2}{243}$

Answer 1

Answer: (C)

$\frac{8}{243}$

$3W+2B+4R$ balls
If three balls are drawn one after another with replacement then
Probability of drawing a white, a black, and a red ball is$=\frac{3}{9}\times \frac{2}{9}\times \frac{4}{9}=\frac{8}{243}$