A bag contains $3$ white and $5$ black balls. One ball is drawn at random. Then the probability that it is white is:

\frac{1}{8}

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\frac{3}{8}

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\frac{5}{8}

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\frac{3}{5}

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Solution

The correct option is C $\frac{3}{8}$
There are $3$ white and $5$ black balls in a bag.
The probability that ball drawn is white is $=$ $\frac{^{3} C_{1}}{^{8} C_{1}} = \frac{3}{8}$

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A bag contains 3 white and 5 black balls. One ball is drawn at random. Then the probability that it is white is:

The correct option is C 38There are 3 white and 5 black balls in a bag.The probability that ball drawn is white is = 3C18C1=38

A bag contains $3$ white and $5$ black balls. One ball is drawn at random. Then the probability that it is white is:

The correct option is C $\frac{3}{8}$
There are $3$ white and $5$ black balls in a bag.
The probability that ball drawn is white is $=$ $\frac{^{3} C_{1}}{^{8} C_{1}} = \frac{3}{8}$