Question

A bag contains $3$ white balls, $4$ green balls and $5$ red balls. Three balls are drawn from the bag without replacement, find the probability that the balls are all of different colors.

• A. $\frac{3}{11}$
• B. $\frac{3}{110}$
• C. $\frac{4}{11}$
• D. $\frac{4}{110}$

Answer 1

Answer: (A)

$\frac{3}{11}$

The required probability will be
$=3!(\frac{3}{12}\times \frac{4}{11}\times \frac{5}{10})$ ...(since the balls can be internally permuted in 3! ways)
$=6\left(\frac{1}{22}\right)$
$=\frac{3}{11}$