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Question

A bag contains 30 balls numbered from 1 to 30. One ball is drawn at random.

A
The probability that the number of the drawn ball will be a multiple of 3 is 1/3
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B
The probability that the number of the drawn ball will be a multiple of 5 is 0.2
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C
The probability that the number of the drawn ball will be a multiple of 7 is 2/15
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D
The probability that the number of the drawn ball will be a multiple of 3 and 5 is 2/15
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Solution

The correct options are
A The probability that the number of the drawn ball will be a multiple of 3 is 1/3
B The probability that the number of the drawn ball will be a multiple of 5 is 0.2
C The probability that the number of the drawn ball will be a multiple of 7 is 2/15
Total number = 30
(A) Probability of the number being multiple of 3 is
P (3, 6, 9, 12, 15, 18, 21, 24, 27,30) =1030=13
(B) Probability of the number being multiple of 5 is P(5, 10, 15, 20, 25, 30) =630=15=0.2
(C) Probability of the number being multiple of 7 is P (7,14, 21,28)=430=115
(D) Probability of the number being multiple of 3 and 5 is P(15,30) =230=115

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