Question

A bag contains 4 green balls, 4 red balls and 2 blue balls. If a ball is drawn from the bag, the
probability of getting neither green nor red ball is

(a) $\frac{2}{5}$ (b) $\frac{1}{2}$ (c) $\frac{4}{5}$ (d) $\frac{1}{5}$

Answer 1

The probability of getting neither green nor red ball is equal to the probability of getting blue balls.
Number of blue balls = 2
Total number of balls = 4 + 4 + 2 = 10
Therefore
Probability of getting neither green nor red ball = $\frac{2}{10}=\frac{1}{5}$
Hence, the correct option is (d).