Question

A bag contains 4 mangoes and 5 oranges. In how many ways can I make a selection so as to take at least one mango and one orange? (All fruits are different)

• A. 465
• B. 365
• C. 8
• D. 19

Answer 1

The correct option is A 465

At least one mango can be selected =$2^4-1=15$ ways. At least one orange can be selected = $2^5-1=31$ ways. Hence, the required number of ways = 15 x 31 = 465 ways.