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Byju's Answer
Standard VIII
Mathematics
Calculating Probability of an Event
A bag contain...
Question
A bag contains 4 red, 5 black and 6 white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is:
(i) white
(ii) red
(iii) not black
(iv) red or white
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Solution
Number
of
red
balls
=
4
Number
of
black
balls
=
5
Number
of
white
balls
=
6
Total
number
of
balls
in
the
bag
=
4
+
5
+
6
=
15
Therefore
,
the
total
number
of
cases
is
15
.
(
i
)
Let
A
denote
the
event
of
getting
a
white
ball
.
Number
of
favourable
outcomes
,
i
.
e
.
number
of
white
balls
=
6
P
A
=
Number
of
favourable
outcomes
Total
number
of
outcomes
=
6
15
=
2
5
(
ii
)
Let
B
denote
the
event
of
getting
a
red
ball
.
Number
of
favourable
outcomes
,
i
.
e
.
number
of
red
balls
=
4
P
B
=
Number
of
favourable
outcomes
Total
number
of
outcomes
=
4
15
(
iii
)
Let
C
denote
the
event
of
getting
a
black
ball
.
Number
of
favourable
outcomes
,
i
.
e
.
number
of
black
balls
=
5
P
C
=
Number
of
favourable
outcomes
Total
number
of
outcomes
=
5
15
=
1
3
Therefore
,
the
probabilty
of
not
getting
a
black
ball
is
as
follows
:
P
C
¯
=
1
-
P
C
=
1
-
1
3
=
2
3
(
iv
)
Let
D
denote
the
event
of
getting
a
red
or
a
white
ball
.
P
D
=
Number
of
favourable
outcomes
Total
number
of
outcomes
=
4
+
6
15
=
10
15
=
2
5
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Similar questions
Q.
A bag contains
6
red balls,
8
white balls,
5
green balls and
2
black balls. One ball is drawn at random from the bag. Find the probability that the ball drawn is
(
i
)
White
(
i
i
)
Red or black
(
i
i
i
)
Not green
(
i
v
)
Neither white nor black
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