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Standard XII

Mathematics

Combination

A bag contain...

Question

A bag contains 4 red 6 blue and 7 yellow balls One ball is selected at random What is the probability that it is blue or yellow ball?

\frac{13}{17}

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\frac{4}{17}

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\frac{6}{17}

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\frac{7}{17}

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Solution

The correct option is A $\frac{13}{17}$
Number of the blue and yellow balls = 6 + 7 =13
Total number of balls = 17
$∴$ Probability of a blue or a yellow ball $\frac{13}{17}$

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A bag contains 4 red 6 blue and 7 yellow balls One ball is selected at random What is the probability that it is blue or yellow ball?

The correct option is A 1317Number of the blue and yellow balls = 6 + 7 =13Total number of balls = 17∴ Probability of a blue or a yellow ball 1317

The correct option is A $\frac{13}{17}$
Number of the blue and yellow balls = 6 + 7 =13
Total number of balls = 17
$∴$ Probability of a blue or a yellow ball $\frac{13}{17}$