A bag contains 3 red balls, 5 black balls and 4 white balls. A ball is drawn at random from the bag. What is the probability of not getting a black ball?

Q. Bag I contains 1 white, 2 black and 3 red balls; Bag II contains 2 white, 1 black and 1 red balls; Bag III contains 4 white, 3 black and 2 red balls. A bag is chosen at random and two balls are drawn from it with replacement. They happen to be one white and one red. What is the probability that they came from Bag III.

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A bag contains 4 red and 3 white balls. A ball is drawn at random from the bag. Find the probability of getting a white ball.

The correct option is B 37The outcome of a ball drawn at random from the bag can be getting a white ball or red ball.Number of white balls=3Total number of balls=7P(white)=37

The correct option is B $\frac{3}{7}$
The outcome of a ball drawn at random from the bag can be getting a white ball or red ball.
Number of white balls= $3$
Total number of balls= $7$
$P ($ white $) =$ $\frac{3}{7}$