Question

A bag contains $4$ red balls, $3$ white balls and $5$ black balls. Two balls are drawn one after the other with replacement. Find the probability that first is red and the second is black.

• A. $\frac{5}{36}$
• B. $\frac{7}{36}$
• C. $\frac{11}{36}$
• D. None of these

Answer 1

The correct option is A $\frac{5}{36}$

probability of drawing red ball $=\frac{4}{12}$

probability of drawing black ball $=\frac{5}{12}$

probability of drawing red ball first and black ball second $=\frac{4}{12}\times \frac{5}{12}=\frac{5}{36}$