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Question

A bag contains 5 black, 7 red, and 3 white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is red, black or white and not a black one.


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Solution

Step 1: Finding the probability that the ball drawn is red:

According to the question, the total number of balls is 5+7+3=15

The total number of red balls is 7

We know that, Probability=NumberoffavorableoutcomesTotalnumberofoutcomes

Therefore,

P(redball)=715

Thus, the probability of drawing a red ball =715

Step 2: Finding the probability that the ball drawn is black or white:

According to the question,

The total number of balls is 5+7+3=15

The total number of black or white balls is 5+3=8

We know that, Probability=NumberoffavorableoutcomesTotalnumberofoutcomes

Therefore,

P(blackorwhiteball)=815

Thus, the probability of drawing a white or black ball=815

Step 3: Finding the probability that the ball drawn is not black:

According to the question, the total number of balls is 5+7+3=15

The total number of black balls is 5

We know that, Probability=NumberoffavorableoutcomesTotalnumberofoutcomes

Therefore,

P(blackball)=515=13

Thus, the probability of drawing a black ball P(E)=515=13

But, this is not what is required.

And, we know that the sum of the probability of occurrence of an event and the probability of non-occurrence of an event is 1.

P(E)+P(E)=1P(black)+P(notblack)=113+P(E)=1P(E)=1-13P(E)=23

Thus, the probability of drawing a ball that is not black is 23.

Hence, from the conclusions made, the probability of drawing a red ball is 715, a white or black ball is 815, not a black ball is 23


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