Question

A bag contains $5$ red and $7$ black balls. If two balls are drawn successively without replacement, then the probability that the first one is red and the second is black is

• A. $\frac{25}{132}$
• B. $\frac{35}{132}$
• C. $\frac{35}{144}$
• D. $\frac{30}{144}$

Answer 1

The correct option is B $\frac{35}{132}$

Probability of getting red ball in first draw=$\frac{5}{12}$
Probability of getting black ball in second draw=$\frac{7}{11}$
So, required probability =$\frac{5}{12}\times \frac{7}{11}=\frac{35}{132}$