A bag contains $5$ red balls, $7$ black balls and $8$ green balls. A ball is drawn randomly from the bag, the probability of getting a red ball is 1/m then the value of $m$ is :

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Solution

The number of Red balls= $5$
Total number of balls or total outcomes $= 5 + 7 + 8 = 20$
Probability of getting a red ball = $\frac{5}{20} = \frac{1}{4}$
$\Rightarrow m = 4$

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A bag contains 5 red balls, 7 black balls and 8 green balls. A ball is drawn randomly from the bag, the probability of getting a red ball is 1/m then the value of m is :

The number of Red balls=5 Total number of balls or total outcomes=5+7+8=20Probability of getting a red ball = 520=14⇒m=4

A bag contains $5$ red balls, $7$ black balls and $8$ green balls. A ball is drawn randomly from the bag, the probability of getting a red ball is 1/m then the value of $m$ is :

The number of Red balls= $5$
Total number of balls or total outcomes $= 5 + 7 + 8 = 20$
Probability of getting a red ball = $\frac{5}{20} = \frac{1}{4}$
$\Rightarrow m = 4$