A bag contains $5$ red balls, $7$ black balls and $8$ green balls. A ball is drawn randomly from the bag, the probability of getting a black ball is 7/m, then Value of $m$ is

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Solution

No. of Black balls = 7
Total number of balls or total outcomes =5+7+8=20
Probability of getting a red ball = $\frac{7}{20}$

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A bag contains 5 red balls, 7 black balls and 8 green balls. A ball is drawn randomly from the bag, the probability of getting a black ball is 7/m, then Value of m is

No. of Black balls = 7Total number of balls or total outcomes =5+7+8=20Probability of getting a red ball = 720

A bag contains $5$ red balls, $7$ black balls and $8$ green balls. A ball is drawn randomly from the bag, the probability of getting a black ball is 7/m, then Value of $m$ is

No. of Black balls = 7
Total number of balls or total outcomes =5+7+8=20
Probability of getting a red ball = $\frac{7}{20}$