Question

A bag contains 5 white, 6 red and 4 green balls. One ball is drawn at random. What is the probability that the ball drawn is
(i) green?
(ii) white?
(iii) non-red?

Answer 1

Total number of balls $=5+6+4=15$
(i) Number of green balls = 4
∴​ ${\mathrm{P}}_{\left(\mathrm{green}\mathrm{ball}\right)}=\frac{4}{15}$

(ii) Number of white balls = 5
∴​ ${\mathrm{P}}_{\left(\mathrm{white}\mathrm{ball}\right)}=\frac{5}{15}=\frac{1}{3}$

(iii) Number of balls that are not red (i.e., 5 white and 4 green)$=9$
∴​ ${\mathrm{P}}_{\left(\mathrm{non}-\mathrm{red}\mathrm{balls}\right)}=\frac{9}{15}=\frac{3}{5}$