Question

A bag contains 5 white, 6 red and 4 green balls. One ball is drawn at random from the bag. What is the probability that the ball drawn is
(i) green
(ii) white
(iii) non-red?

Answer 1

Total number of possible outcomes = Total number of balls

= ( 5 + 6 + 4) = 15

(i) Number of green balls = 4

∴ P (getting a green ball ) = $\frac{4}{15}$

(ii) Number of white balls = 5
∴ P (getting a white ball ) = $\frac{5}{15}=\frac{1}{3}$

(iii) Total number of non-red balls = 9
∴ P (getting a non-red ball ) = $\frac{9}{15}=\frac{3}{5}$