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Question

A bag contains 5 white and 3 black balls. Four balls are successive drawn out without replacement. What is the probability that they are alternately of different colours?

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Solution

Total number of balls =5+3=8
Probabiliyt of getting one white ball =58
Number of remaining balls =81=7
out of them there are 4 white and 3 black balls
Probability of being black ball =37
Number of remaining balls =71=6 where are 4 white and 2 black balls
Probability of being third white ball =46
Number of remaining balls =61=5
where are 3 white and 2 black
Probability of being fourth black ball =25
Events are independent every time
Probability of being different colours ball
=58×37×46×25×2
=114×2=17

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