Question

A bag contains $5$ white balls, $6$ red balls and $9$ green balls. A ball is drawn at random from the bag. Find the probability that the ball drawn is :
(i) a green ball.
(ii) a white or a red ball.
(iii) is neither a green ball nor a white ball.

Answer 1

$\frac{White}{5}$ $\frac{Red}{6}$ $\frac{Green}{9}$
Total number of balls $=5+6+9$
$=20$
(i) Probability $=\frac{favourablecases}{Totalcases}$
P(Green) $=\frac{9}{20}$
(ii) P(White or red) $=\frac{5+6}{20}$
$=\frac{11}{20}$
(iii) P(neither green nor white) $=$ P(Red)
$=\frac{6}{20}$
$=\frac{3}{10}$