Question

A bag contains $5$ white balls, $7$ red balls, $4$ black balls and $2$ blue balls. One ball is drawn at random from the bag. What is the probability that the ball drawn is neither white nor black?

Answer 1

Total number of balls $=5+7+4+2=18$

Number of balls which are neither white nor black $=$ Number of balls which are red or blue $=7+2=9$

Required probability $=\frac{favourableoutcomes}{Totaloutcomes}=\frac{9}{18}=\frac{1}{2}$