Question

A bag contains $50p$, $25p$ and $10p$ coins in the ratio $5:9:4$ amounting to Rs. $206$. Find the number of $50p$ coins.

Answer 1

Let the number of $50p$, $25p$ and $10p$ coins be $5x$, $9x$ and $4x$ respectively.

Then,
$\frac{50\times 5x}{100}+\frac{25\times 9x}{100}+\frac{10\times 4x}{100}=206$
$\Rightarrow \frac{5x}{2}+\frac{9x}{4}+\frac{4x}{10}=206$

$\Rightarrow 50x+45x+8x=4120$
$\Rightarrow x=40$
$\therefore$ Number of $50p$ coins $=(5\times 40)=200$
Number of $25p$ coins $=(9\times 40)=360$
Number of $10p$ coins $=(4\times 40)=160$