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Standard VI

Mathematics

Word Problems

A bag contain...

Question

A bag contains 50 paise, 1 rupee and 2 rupee coinsintheratio 2:3:4. If the total amount is Rs 240, what is the total number of coins?

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162

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180

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225

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Solution

The correct option is C 180
Total value in one set $= R s (2 \times \frac{1}{2} + 3 \times 1 + 4 \times 2) = R s 12$ .
Number of sets $= 240 \div 12 = 20$
$∴$ Total number of coins $= 20 \times 9 = 180$ .

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A bag contains 50 paise, 1 rupee and 2 rupee coinsintheratio 2:3:4. If the total amount is Rs 240, what is the total number of coins?

The correct option is C 180Total value in one set =Rs(2×12+3×1+4×2)=Rs12.Number of sets =240÷12=20∴ Total number of coins =20×9=180.

The correct option is C 180
Total value in one set $= R s (2 \times \frac{1}{2} + 3 \times 1 + 4 \times 2) = R s 12$ .
Number of sets $= 240 \div 12 = 20$
$∴$ Total number of coins $= 20 \times 9 = 180$ .