Question

A bag contains 6 blue, 3 violet and 7 grey balls. Two balls are drawn at random without replacement. What's the type of event if both the balls drawn are violet?

• A. Dependent
• B. Independent

Answer 1

The correct option is A Dependent

Given: $6$ blue, $3$ violet and $7$ grey balls

Let A be the event of picking first violet ball.

So,Probability of choosing first violet ball is $\text{P(A)}=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

$\Rightarrow \text{P(A)}=\frac{3}{16}$

Similarly, B be the event of picking second violet ball.

So, Probability of picking second violet ball without replacement is $\text{P(B)}=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

$\Rightarrow \text{P(B)}=\frac{2}{15}$

Clearly, the probabilty of drawing second ball depends on that of the first.

So, these event are dependent.