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Standard XII

Mathematics

Independent Events

A bag contain...

Question

A bag contains 6 red and 4 blue balls (all are different). A fair die is rolled and number of balls equals to that appearing on the die is chosen from the bag at random. The probability that all the balls selected are red is

\frac{127}{630}

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\frac{1}{5}

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\frac{1}{30}

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\frac{1}{6}

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Solution

The correct option is B $\frac{1}{5}$
Given number of red balls =6, number of blue balls = 4
Therefore required probability $= \frac{1}{6} {\frac{6 C_{1}}{10 C_{1}} + \frac{6 C_{2}}{10 C_{2}} + \frac{6 C_{3}}{10 C_{3}} + \frac{6 C_{4}}{10 C_{4}} + \frac{6 C_{5}}{10 C_{5}} + \frac{6 C_{6}}{10 C_{6}}} = \frac{1}{5}$

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A bag contains 6 red and 4 blue balls (all are different). A fair die is rolled and number of balls equals to that appearing on the die is chosen from the bag at random. The probability that all the balls selected are red is

The correct option is B 15Given number of red balls =6, number of blue balls = 4 Therefore required probability =16{6C110C1+6C210C2+6C310C3+6C410C4+6C510C5+6C610C6}=15