A bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball from the bag is twice that of a red ball, find the number of blue balls in the bag.
Given Red balls = 6
Let Blue balls = B
Total balls = B + 6
P(E)of blue balls is double than red balls
then
P(E) blue = 2 x P(E) red
= 2 x
B = 12
Therefore there are a total of 12 blue balls.