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Question

A bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball from the bag is twice that of a red ball, find the number of blue balls in the bag.

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Solution

Given Red balls = 6

Let Blue balls = B

Total balls = B + 6

P(E)of blue balls is double than red balls

then

P(E) blue = 2 x P(E) red

fraction numerator B over denominator B plus 6 end fraction = 2 x fraction numerator 6 over denominator B plus 6 end fraction

B = 12

Therefore there are a total of 12 blue balls.


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