Question

A bag contains $6$ white balls numbered $1$ to $6$ and $4$ red balls numbered $7$ to $10$. Find the probability of getting an odd number ball.

Answer 1

Finding the probability of getting an odd number ball.

Let $\text{P}\left(\text{E}\right)$ be the probability of getting a ball with odd number on it.

Total number of balls$=6\left(\text{white}\right)+4\left(\text{red}\right)$

$=10$

$\therefore$Number of possible outcomes$=10$

Balls with odd number of it$=1,3,5,7$ and $9$

$\therefore$Number of possible outcomes$=5$

We know that $\text{P}\left(\text{E}\right)\text{=}\frac{\text{Number of favourable outcomes}}{\text{Number of possible outcomes}}$

So, $\text{P}\left(\text{E}\right)$$=\frac{5}{10}$

$=\frac{1}{2}$

Hence, probability of getting an odd number ball$=\frac{\mathbf{1}}{\mathbf{2}}$